Originally Posted by Andrew R WarlordTony, I'm sure he declares it in a config.php file. PHP Code: $query = sprintf("SELECT password FROM %s_admin WHERE admin_name='%s'", $prefix, $cookie[1]); $result = mysql_query($query);  Try that.

Warlord tony is correct, how can he declare a variable and call it WITHIN a function without using globals?

Id imagine this is the source of his errors aswell.